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calculati [0,(3)+1,(3):un intreg7/9](1+1/12

Răspuns :

Renatemambouko
 [0,(3)+1,(3):1 7/9](1+1/12)=
= [3/9+(13-1)/9:16/9](12+1)/12=
= [1/3+12/9×9/16]13/12=
= [1/3+12/16]13/12=
= [1/3+3/4]13/12=
= (4+9)/4×13/12=
= 13/12×13/12=
=169/144=
=1,1736(1)


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