Răspuns :
ducemAM_I_BC
BM=MC=2:2=1
AM=√(2²-1²)=√3
d(N,BC)=NM=√[12²+(√3)²]=√(144+3)=√147=7√3 cm
BM=MC=2:2=1
AM=√(2²-1²)=√3
d(N,BC)=NM=√[12²+(√3)²]=√(144+3)=√147=7√3 cm
Fie AD, perpendiculara din A pe BC
AD²+BD²=AB²
AD²=AB²-BD²(BD=BC/2)
=4-1
AD=√3
ND²=AD²+AN²
=(√3)²+(12)²
=3+144
=147
ND=√147
AD²+BD²=AB²
AD²=AB²-BD²(BD=BC/2)
=4-1
AD=√3
ND²=AD²+AN²
=(√3)²+(12)²
=3+144
=147
ND=√147