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Marius5000
a fost răspuns

Y=[(11-0^11)x(3^3-3^2)+1^2000]x(3^2-2^3)-3^2x2=

Răspuns :

CarMina03
Y=[(11-0¹¹)x(3³-3²)+1²°°°]x(3²-2³)-3²x2=[(11-0)x(27-9)+1]x(9-8)-9x2=(11x18+1)x1-18=(11x18+1)x1-18=(198+1)-18=199-18=181
Y=[(11-0¹¹)x(3³-3²)+1²⁰⁰⁰]x(3²-2³)-3²x2y=[(11-0)x(27-9)+1]x(9-8)-9x2
y=(11x18+1)x1-18
y=198+1)x1-18
y=199-18
y=181