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Calculat radical2x+1 stiind ca x egal cu 1+3+3 la puterea 2 +3 la putera 3+.....3 la puterea 2013

Răspuns :

   
[tex]\displaystyle \\ x =1+3+3^2 +3^3+ \cdots +3^{2013} = \boxed{\frac{3^{2014}-1}{2}} \\ \\ \\ \sqrt{2x+1} = \sqrt{2\cdot\frac{3^{2014}-1}{2}+1} = \sqrt{3^{2014}-1+1} = \sqrt{3^{2014}} =\boxed{\boxed{3^{1007}}}[/tex]



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