Răspuns :
x²+5x+6 /x²-9
x²+2x+3x+6 /x²-9
x(x+2)+3(x+2) /(x+3)(x-3)
(x+3)(x+2)/(x+3)(x-3)
x+2 /x-3
unde x∈R-{-3,3}
x²+2x+3x+6 /x²-9
x(x+2)+3(x+2) /(x+3)(x-3)
(x+3)(x+2)/(x+3)(x-3)
x+2 /x-3
unde x∈R-{-3,3}