Răspuns :
x³+ 3x² - 6x - 8 =
=x³ -2³ + 3x(x -2) =
=(x -2)(x²+2x+4) + 3x(x -2) =
=(x -2)(x²+2x+4+ 3x) =
=(x -2)(x²+5x+4) =
=(x -2)(x²+4x+x+4) =
=(x -2)[x(x+4)+(x+4)] =
=(x -2)(x+4)(x+1)
=x³ -2³ + 3x(x -2) =
=(x -2)(x²+2x+4) + 3x(x -2) =
=(x -2)(x²+2x+4+ 3x) =
=(x -2)(x²+5x+4) =
=(x -2)(x²+4x+x+4) =
=(x -2)[x(x+4)+(x+4)] =
=(x -2)(x+4)(x+1)