Răspuns :
fie numerele
a, b=a+1, c=a+2, c=a+3 (deoarece sunt consecutive)
a+(a+1)+(a+2)+(a+3)=806
4a=806-6
4a=800
a=800:4
a=200
b=a+1=201
c=a+2=202
d=a+3=203
a=200, b=201, c=202, d=203
verificare
a+b+c+d=806
200+201+202+203=806
806=806
a, b=a+1, c=a+2, c=a+3 (deoarece sunt consecutive)
a+(a+1)+(a+2)+(a+3)=806
4a=806-6
4a=800
a=800:4
a=200
b=a+1=201
c=a+2=202
d=a+3=203
a=200, b=201, c=202, d=203
verificare
a+b+c+d=806
200+201+202+203=806
806=806