👤
a fost răspuns

determinati toate numerele naturale de trei cifre care impartite , pe rand, la un numar de doua cifre dau restul nouazeci si opt.

Răspuns :

Bebedumi70
D=I*C+R......=>...R<I......=>...98<99....=>...I=99   

  98:99=0 rest 98....................89+99=197............=>
197:99=1 rest 98..................197+99=296
296:99=2 rest 98..................298+99=395
395:99=3 rest 98..................395+99=494
494:99=4 rest 98......etc...
593:99=5 rest 98
692:99=6 rest 98
791:99=7 rest 98
890:99=8 rest 98
989:99=9 rest 98

R=> 98;197;296;395;494;593;692;791;890;989
..

Alte intrebari