Răspuns :
(x+√2-√3)²=(x+√2-√3)×(x+√2-√3)=
=x²+x√2-x√3+x√2+2-√6-x√3-√6+3
=x²+2x√2-2x√3-2√6+3
=x²+2(x√2-x√3-√6)+3
=x²+x√2-x√3+x√2+2-√6-x√3-√6+3
=x²+2x√2-2x√3-2√6+3
=x²+2(x√2-x√3-√6)+3
(x+√2-√3)²=(x+√2-√3)×(x+√2-√3)=
x²+x√2-x√3+x√2+2-√6-x√3-√6+3
x²+2x√2-2x√3-2√6+3
X²+2(x√2-x√3-√6)+3