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1+3+5+...297+299=pp este patrat perfect?

Răspuns :

Icecon2005
1+3+5+...297+299 progre3sie aritmetica
an=a1+(n-1)×r
299=1+(n-1)×2
299-1+2=2n
300=2n
n=150
S=[(a1+an)×n]:2=[(1+299)×150]:2=(300×150):2=(×150300:2)=150×150=150²

1+3+5+...297+299 =150² -patrat perfect

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