Răspuns :
[tex]5 \sqrt{3}(4 \sqrt{12} -2 \sqrt{27} )= \\
12|2 ~~~~~~~~~~~27|3\\
~~~6|2 ~~~~~~~~~~~~9|3\\
~~~3|3~~~~~~~~~~~~3|3 \\
\sqrt{12}=2 \sqrt{3} \\
\sqrt{27}=3 \sqrt{3} \\
5 \sqrt{3}( 4*2 \sqrt{3}-2*3 \sqrt{3})= \\
5 \sqrt{3}(8 \sqrt{3}-6 \sqrt{3})= \\
5 \sqrt{3}* 2 \sqrt{3}= \\
10*( \sqrt{3})^2= \\
10*3=\boxed{30}
[/tex]