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a fost răspuns

Descompuneti in factori:
a) (x+5)(2x-1)^2-16 (x+5)
b) (3x-1)^2 -4 (x+1)^2

Răspuns :

Bunicaluiandrei
a) (x+5)[(2x-1)² - 16] = (x+5)(2x-1+4)(2x-1-4) = (x+5)(2x+3)(2x-5)
b) [3x-1 + 2(x+1)][3x-1-2(x+1)] = (5x+1)(x-2)

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