Răspuns :
multimea A = {0,1,2,3,4,5,6}
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[tex] 2^{x} \ \textless \ 70; 2^{2}=4 . . 2^{6}=64 [/tex]
deci multimea B= { 0,1,2,3,4,5,6}
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[tex]2 \leq (x+2) \leq 8 [/tex]
Scad un 2 inecuatiei si obtin:
[tex]0 \leq x \leq 6[/tex]
deci multimea C={0,1,2,3,4,5,6}
Concluzie: cele 3 multimi sunt egale
__
[tex] 2^{x} \ \textless \ 70; 2^{2}=4 . . 2^{6}=64 [/tex]
deci multimea B= { 0,1,2,3,4,5,6}
___
[tex]2 \leq (x+2) \leq 8 [/tex]
Scad un 2 inecuatiei si obtin:
[tex]0 \leq x \leq 6[/tex]
deci multimea C={0,1,2,3,4,5,6}
Concluzie: cele 3 multimi sunt egale
A={0,1,2,3,4,5,6} B={0,1,2,3,4,5.....,69} C={0,1,2,3,4,5,6} Toate multimile sunt egale