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Raportul masurilor a doua unghiuri suplementare este 2 supra 3.Determinati masurile celor doua unghiuri

Răspuns :

Solaris
Notăm cu x, y- măsurile => 180 = x + y şi x/y = 2/3 => 3x = 2y => y = 3x/2 => x + 3x/2 = 180 |•2 => 2x + 3x = 360 => x = 360/5 = 72° şi y = 180 - 72 = 108°
MadalinaMadutaa
[tex] \frac{a}{b}= \frac{2}{3} \\\\ =\ \textgreater \ b= \frac{3a}{2} \\\\ a+b=180\°\\\\ Inlocuim:\\\\ \frac{3a}{2} +a=180\\\\ \frac{3a+2a}{2} =180\\\\ \frac{5a}{2} =180\\\\ 5a=180*2\\\\ 5a=360\\\\ a= \frac{360}{5} \\\\ a=72\°\\\\ b= \frac{3a}{2} \\\\ b= \frac{3*72}{2} \\\\ b= \frac{216}{2} \\\\ b=108\°[/tex]

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