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Lorenaclaudio2
a fost răspuns

3^2x[3^2x(x:3^2-222)+1^0]+1^1999=10

Răspuns :

Renatemambouko
3^2×[3^2×(x:3^2-222)+1^0]+1^1999=10
9×[9×(x:9-222)+1]+1=10
9×[9×(x:9-222)+1]=9
9×(x:9-222)+1=1
9×(x:9-222)=0
x:3^2-222=0
x:3^2=222
x=222*3^2=1998





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