A (1,4), B(3,2) , C(4,6)
M-este mijlocul vectorului BC.
=> [tex]M( \frac{3+4}{2}, \frac{2+6}{2}) [/tex]
=> [tex]M( \frac{7}{2},4) [/tex]
Acum calculam ecuatia dreptei AM, A(1,4); M(7/2,4)
[tex] \left|\begin{array}{ccc}x&y&1\\1&4&1\\ \frac{7}{2} &4&1\end{array}\right| =0 \\ \\ 4x+4+ \frac{7y}{2} -14-4x-y = 0 \\ \frac{5y}{2} -10 = 0 \\ \frac{5y}{2}=10 \\ 5y= 20 \\ y=4[/tex]
=> y=4 este ecuatia medianei AM.
