solutie 1 : pH = 13 ⇒ [H⁺] = 10⁻¹³ moli/l [HO⁻] = [KOH]1 = 10⁻¹ moli/l Vs1
solutie 2 : pOH = 3 [HO⁻] = 10⁻3 moli/l = [KOH]2 Vs2
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solutia finala Vs = Vs1 + Vs2 [KOH]=10⁻²moli/l ([H⁺] = 10⁻¹² [HO⁻] = 10⁻2)
nd1 = c1ₓVs1 = 10⁻¹ₓVs1
nd2 = c2ₓVs2 = 10⁻³ₓVs2 nd = 10⁻¹Vs1 + 10⁻³Vs2
10⁻¹ₓ(Vs1+ 10⁻²Vs2)/(Vs1+ Vs2) = 10⁻²
10⁻¹ₓ(Vs1 + Vs2) = Vs1 + 0,01Vs2 Vs1 + Vs2 = 10Vs1 + 0,1Vs2
0,9Vs2 = 9Vs1 Vs2/Vs1 = 9/0,9 = 10/1
