Răspuns :
teorema impartirii cu rest zice asa daca D:I=c si rest atunci D=Ixc+r
d=ixc+r
d+i=2016
ixc+r+i=2016
i(c+1)+r=2016
i(105+1)+2=2016
106i=2016-2
106i=2014
i=2014:106
i=19
d=ixc+r=19x105+2=1995+2=1997
d=ixc+r
d+i=2016
ixc+r+i=2016
i(c+1)+r=2016
i(105+1)+2=2016
106i=2016-2
106i=2014
i=2014:106
i=19
d=ixc+r=19x105+2=1995+2=1997
D:I=C, rest R =>D=C·I+R sau D=105·I+2
D+I=2016
Inlocuim pe D in a doua expresie si avem :
(105·I+2)+I=2016
106·I=2014 =>I=19 =>D=2016-19 =>D=1997
D+I=2016
Inlocuim pe D in a doua expresie si avem :
(105·I+2)+I=2016
106·I=2014 =>I=19 =>D=2016-19 =>D=1997