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Stefys02
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care ste ultim cifra a sumei numerelor 2 la [puterea] 2014+6 la a 2014+1?

Răspuns :

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[tex]u(2^{2014}+6^{2014}+1)= \\ \\ u(2^{2014})=4~pt.~ca: \\ \\ 2014:4=503~r~2;u(2^0)=1;u(2^1)=2;u(2^2)=4 \\ \\ u(6^{2014})=6~pt.~ca: \\ \\  u(6^1)=6;u(6^2)=6;u(6^3)=6~etc. \\ \\ u(4+6+1)=u(11)=1[/tex]
[tex] U(c)2^{2014} =2014:4=503\ \ rest\ \ 2=>2^2=4 \ \ deci\ \ U(c)=4 \\ \\ U(c)6^{2014}=6 \\ \\ U(c)2^{2014}+6^{2014}+1=4+6+1=11 =>\boxed{\boxed{U(c)=1}}[/tex]