Răspuns :
numerele consecutive sunt: a; a+1 si a+2
=> ( a + a+1 + a+2 ):3 = 23
3a + 3 = 69
3a = 66
a = 22
=> R: 22 ; 23 ; 24 .
=> ( a + a+1 + a+2 ):3 = 23
3a + 3 = 69
3a = 66
a = 22
=> R: 22 ; 23 ; 24 .
Raspuns (A+B+C) : 3=23 /x3 A+B+C=69 A=22 B=23 C=24
(22+23+24) : 3=
69 : 3=23
(22+23+24) : 3=
69 : 3=23