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Bogdanclaudiu7
a fost răspuns

Descompuneti in factori:
4(x-1)^2 - 4(x-1) + 1

(5x^2 - 1)^2 - y^2

7x^2 - 1

(2x-1)^2 - (x+3)^2

(4x-1)^2 -(5x+1)^2

a^4 - 4a^3 + 6a^3 - 4a +1



Răspuns :

Danaradu70
not x-1=y
4y^2-4y+1=(1-2y)^2=[1-2x+2]^2=(3-2x)^2

a^2-b^2=(a-b)(a+b)
=(5x^2-1-y^2)(5x^2-1+y^2)

[2x-1-(x+3)][2x-1+x+3]=(x-4)(3x+2)

[4x-1-(5x+1)][4x-1+(5x+1)]=(-x-2)*9x

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