(1+2+3+4+...+100)- (1+2+...+11) 1+2+3+...+100 =(100×101)÷2=50×101=5050 1+2+3+...+11= (11×12)÷2=11×6=66 5050-66= 4984 4984=5(1000x-1) 4984=5000x-5=> 5000x=4984+5 5000x=4989 x=4989÷5000 => x=0,9974 nu stiu daca sigur este bine .. sper ca te am ajutat cu cv