n1 moli C2H5Cl n1 moli de atomi de Cl 35,5n1 g
n2 moli C2H4Cl2 2n2 moli atomi de Cl 71n2 g
m amestec = 64,5n1 + 99n2 (35,5n1+ 71n2)·100/(64,5n1 +99n2 ) = 67,62
(n1 + 2n2)·52,5 = 64,5n1 + 99n2
12n1 = 6n2 n2 = 2n1
1. %C2H5Cl = n1·100/3n1 = 33,33%; %C2H4Cl2 = 2n1·100/3n1 = 66,66%
2. 2CH4 ⇒HC≡CH + 3H2
HC≡CH + HCl ⇒ H2C=CHCl +HCl ⇒ H3C-CHCl2