Răspuns :
b-a=4intreg 3/4⇒b-a=(4·4+3)/4⇒b-a=19/4
a=b/5 inlocuim in relatia a-b=19/4
⇒b-b/5=19/4
(5b-b)/5=19/4
4b/5=19/4
4b·4=19·5
b=95/16
a=95/16:5/1=95/16·1/5=95/80
a=95/80 simplif.cu5=19/16
a=b/5 inlocuim in relatia a-b=19/4
⇒b-b/5=19/4
(5b-b)/5=19/4
4b/5=19/4
4b·4=19·5
b=95/16
a=95/16:5/1=95/16·1/5=95/80
a=95/80 simplif.cu5=19/16
a-b=19/4
b=a:5
a-a/5=19/4 aducem la acelasi numitor si avem
20a-4a=95
16a=95
a=95/16
b=95/16*1/5
b=19/16 proba;
95/16-19/16=76/16 se simplifica cu 4 si da ; 19/4 adica 4 intregi si 3/4
b=a:5
a-a/5=19/4 aducem la acelasi numitor si avem
20a-4a=95
16a=95
a=95/16
b=95/16*1/5
b=19/16 proba;
95/16-19/16=76/16 se simplifica cu 4 si da ; 19/4 adica 4 intregi si 3/4