mK=19,5 Kg
a)mKCO3=?
b) mKClO4=?
c)mKCl=?
d) mKCO2=?
a) MKClO3=39+35,5+3*16=122,5
122,5......39 gK
x...............19,5 x=61,25
b) MKClO4=39+35.5+4*16=138,5
138,5..........39 g K
y....................19,5g
y=69,25
c) MKCl=39+35,5=74,5
74,5g KCl........39g K
z.....................19,5g K Z=37,25
d) MKClO2=39+35,5+2*16=106,6
106,5.gKClO2.........39 g K
t................................19,5 t=53,25
