a) (4/9)ˣ⁺¹ × (27/8)ˣ =2/3 ⇔ (2/3)²⁽ˣ⁺¹⁾ × (3/2)³ˣ=2/3 ⇔ (2/3)²ˣ⁺² × (2/3)⁻³ˣ=(2/3)¹ ⇔ (2/3)²ˣ⁺²⁻³ˣ=(2/3)¹ ⇔ 2x+2-3x=1 ⇔ 2x-3x=-2 ⇔ -x=-2 ⇒ x=2
b)(3/11)³ˣ⁻¹⁰ = (11/3)⁷ˣ⁻¹⁰ ⇔ (3/11)³ˣ⁻¹⁰ = (3/11)⁻⁽⁷ˣ⁻¹⁰⁾ ⇔ (3/11)³ˣ⁻¹⁰ = (3/11)⁻⁷ˣ⁺¹⁰ ⇔ 3x- 10=-7x+10 ⇔ 3x+7x=10+10 ⇔ 10x=20 ⇔x=20:10 ⇒ x=2
c) (0,25)³⁻ˣ = 256/2ˣ⁺⁵ ⇔ (1/4)³⁻ˣ=256× 2⁻ˣ⁻⁵ ⇔ (1/2)²⁽³⁻ˣ⁾ =2⁸ × 2⁻ˣ⁻⁵ ⇔ (1/2)⁶⁻²ˣ=2⁸ × 2⁻ˣ⁻⁵ ⇔ 2⁻⁽⁶⁻²ˣ⁾=2⁸ × 2⁻ˣ⁻⁵ ⇔ 2⁻⁶⁺²ˣ=2⁸⁻ˣ⁻⁵ ⇔ -6+2x=8-x-5 ⇔ 2x+x=8-5+6 ⇔ 3x=9 ⇔ x=9:3 ⇒ x=3
