Răspuns :
t+m+f=89
t-n=34
m-n=29
f-n=5
t=34+n
m=29+n
f=5+n
34+n+29+n+5+n=89
3n+68=89
3n=89-68
3n=21
n=7(in urma cu 7 ani)
t=34+7=41
m=29+7=36
f=5+7=12
t-n=34
m-n=29
f-n=5
t=34+n
m=29+n
f=5+n
34+n+29+n+5+n=89
3n+68=89
3n=89-68
3n=21
n=7(in urma cu 7 ani)
t=34+7=41
m=29+7=36
f=5+7=12
t+m+f=89
34+a+29+a+5+a=89
3a=89-(34+29+5)
3a=89-68
3a=21
a=21:3
a=7 ( in urma cu 7 ani )
34+7=41 ani are tata
29+7=36 ani are mama
5+7=12 ani are fiul
V: 41+36+12=89
34+a+29+a+5+a=89
3a=89-(34+29+5)
3a=89-68
3a=21
a=21:3
a=7 ( in urma cu 7 ani )
34+7=41 ani are tata
29+7=36 ani are mama
5+7=12 ani are fiul
V: 41+36+12=89