Răspuns :
3a + 2b =16
inmultim cu 3
[3a + 2b =16 ]×3⇒3×3a+3×2b=3×16⇒9a+6b=48
9a +(5 +6b)=9a+5+6b=(9a+6b)+5=48+5=53
deci
9a +(5 +6b)=53
inmultim cu 3
[3a + 2b =16 ]×3⇒3×3a+3×2b=3×16⇒9a+6b=48
9a +(5 +6b)=9a+5+6b=(9a+6b)+5=48+5=53
deci
9a +(5 +6b)=53