a+b+c=297
a:b=2 rest 25, a=2b+25, 2b=a-25, b=(a-25)/2
a:c=11 rest 8, a=11c+8, 11c=a-8, c=(a-8)/11
introduc in prima relatie
[tex]a+ \frac{a-25}{2} + \frac{a-8}{11} =297[/tex]
aduc la acelasi numitor care e 22
amplific cu 22 , 11, 2 respectiv 22 si renunt la numitor
22a+ 11(a-25)+2(a-8)=297*22
22a+11a - 275+2a-16=297*22
35a-291=6534
35a=6534+291=6825
a=6825:35=195
b=(a-25):2=170:2=85
c=(a-8)/11=187/11=17
