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a fost răspuns

aflati numerele a si b din egalitatile
parantexa patrata(a+116 :2)ori 3+4inchide parantexa patrata ori 11 =1991
(b:11-4):3-110:2=4
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Răspuns :

a) [(a+116:2)*3+4]*11=1991
[(a+58)*3+4]=1991:11
(a+58)*3+4=181
(a+58)*3=181-4
(a+58)*3=177
3a+174=177
3a=3
a=1

(b:11-4):3-110:2=4
(b:11-4):3-55=4
(b:11-4):3=4+55
(b:11-4):3=59
b:11-4=59*3
b:11-4=177
b:11=177+4
b:11=181
b=181*11
b=1991