Răspuns :
a,a+1,a+2,a+3=nr consecutive
a+a+1+a+2+a+3=302
4a+6=302/-6
4a=296/:4
a=74
a+1=75
a+2=76
a+3=77
a+a+1+a+2+a+3=302
4a+6=302/-6
4a=296/:4
a=74
a+1=75
a+2=76
a+3=77