n1 moli HCl + NaOH ⇒ NaCl + H2O
n2 moli H2SO4 + 2NaOH ⇒ Na2SO4 + 2H2O
n1/n2 = 3/2 nNaOH = 7·40/40 = 7 moli
n1 + 2n2 = 7
2n1 - 3n2 = 0 7n1 = 21 n1 = 3 moli HCl n2 = 2moli H2SO4
a) %HCl = 3·36,5·100/1000 = 10,95%
b) %H2SO4 = 2·98·100/1000 = 19,6%
c) nNaCl = nHCl = 3 moli nNa2SO4 = n H2SO4 = 2 moli
nNaCl/nNa2SO4 = 3/2
d) ms final = 1700g md = 3·58,5 = 175,5g
c = 17550/1700 = 10,32%
e) md = 2·142 = 284g c = 28400/1700 = 16,7%