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Daca adaugam 60g apa pentru o solutie de alcool 50% obtinem o solutie de alcool c= 40% Cate g de solutie 40% obtinem? Cate g avea solutia de concentratie 50% ?

Răspuns :

Lorennapop
Stim ca c=md*100/ms => md*100/ms initial=50 => md/ms initial=0,5 => md=0,5ms initial
md*100/(ms initial + 60)=40 => md/ms initial +60=0,4 => md=0,4 ms initial + 24
md= 0,5ms initial
0,4ms initial + 24= 0,5ms initial => 24=0,1ms initial =>ms initial=240 g (de 50%)
ms final= 240 + 60= 300 g (de 40%)

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