Răspuns :
a+b=27
a-fete
b-baieti
a=b+25b/100=(100b+25b)/100=125b/100=5b/4
5b/4+b=27
(5b+4b)4=27
9b/4=27
b=27x4/9=12 baieti
a=27-b=27-12=15 fete
a-fete
b-baieti
a=b+25b/100=(100b+25b)/100=125b/100=5b/4
5b/4+b=27
(5b+4b)4=27
9b/4=27
b=27x4/9=12 baieti
a=27-b=27-12=15 fete
b-baieti f-fete
b+f=27
f=25%xb+b=25/100b+b=5b/4
b+5b/4=27 aducem la acelasi numitor comun adica 4
4b+5b=108
9b=108
b=12
f=27-12=15
b+f=27
f=25%xb+b=25/100b+b=5b/4
b+5b/4=27 aducem la acelasi numitor comun adica 4
4b+5b=108
9b=108
b=12
f=27-12=15