Răspuns :
Fie numerele n, n+1, n+2
(n+n+1+n+2)/3=13 =>3n+3=39 =>3n=36 =>n=12
Numerele sunt 12, 13 si 14.
(n+n+1+n+2)/3=13 =>3n+3=39 =>3n=36 =>n=12
Numerele sunt 12, 13 si 14.
[tex] \frac{a+a+1+a+2}{3}=13 =\textgreater a+a+1+a+2=13*3 =\textgreater 3a+3=39 [/tex]
[tex] 3a=36 [/tex]
[tex] a=\frac{36}{3}=12 [/tex]
[tex] Nr \ sunt \ 12,13,14 [/tex]
[tex] 3a=36 [/tex]
[tex] a=\frac{36}{3}=12 [/tex]
[tex] Nr \ sunt \ 12,13,14 [/tex]