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Izabellaalbert
a fost răspuns

daca 4a+5b+2c=88 si 4ax+5bx+2cx=352 determinati x urmatorul;

determinati 10x+27y+9z,stiind ca 2x+3y=17si 4y+3z=74

Răspuns :

Gabcen71
4ax+5bx+2cx=352
x(4a+5b+2c)=352
x·88=352
x=352:88
x=4


CarMina03
4ax+5bx+2cx=352x(4a+5b+2c)=352
x88=352
x=352:88
x=4

10x+27y+9z=10x+15y+12y+9z=5(2x+3y)+3(4y+3z)=5*17+3*74=85+222=307



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