[tex]\displaystyle 9e). \frac{xy+y^2}{a-3b} : \frac{x^2-y^2}{2a-6b}= \frac{y(x+y)}{a-3b} : \frac{(x-y)(x+y)}{2(a-3b)} = \\ \\ = \frac{y(x+y)}{a-3b} \cdot \frac{2(a-3b)}{(x-y)(x+y)} = \frac{2y}{x-y}[/tex]
[tex]\displaystyle f). \frac{y-8}{x^2-4} : \frac{2y-16}{3x-6} = \frac{y-8}{(x-2)(x+2)} :
\frac{2(y-8)}{3(x-2)} = \\ \\ =\frac{y-8}{(x-2)(x+2)} \cdot
\frac{3(x-2)}{2(y-8)} = \frac{3}{2(x+2)} [/tex]
[tex]\displaystyle g). \frac{a^2-9}{a^2+6a+9} : \frac{3-a}{a+3} = \frac{(a-3)(a+3)}{(a+3)^2} : \frac{3-a}{a+3} = \\ \\ =\frac{(a-3)(a+3)}{(a+3)^2} \cdot \frac{a+3}{3-a} =-1[/tex]
