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Mihacodreanu99
a fost răspuns

Formula molecuara pt :
-cicloalchena care contine 11,764%H
- alchena care formeaza prin aditiede brom un compus ce contine 65,57% Br
-alchena a carei masa creste cu 32,14% prin aditia apei

Răspuns :

Moonlight01
1. CnH2n-2 = 14n-2

℅H=mH/M*100=>11,764=(2n-2)/(14n-2)*100=>164,696n-23,528=200n-200=>35,304n=176,472=>n=5

F.M => C5H10 -> ciclopentena

2. CnH2nBr => 14n+80

℅Br=mBr/M*100=>65,57=80/14n+80*100=>n=3.

F.M => C3H6


3. CnH2n+2O => 14n+18

14n............100
14n+18......132,14

=>n=4

F.M => C4H8