Răspuns :
CH=C(CH3)-CH2-CH3+4O-----.>CO2 +H2O+ CH3-C-CH2-CH3
II
O
-CALCULEZ masa de compus pur
p/100= m,pur/m,impur-
80/100= m,pur/26,25----> m,pur= 21g
-calculez numar de moli compus, cu M(miu)=(5x12gC+10gH)/mol=70g/mol
n(niu)= m/M
n= 21g/70g/mol=0,3mol 2metil 1 butena
- calculez moli O, din ecuatie
1mol compus..........4molO
0,3mol..........................x= 1,2molO
-calculez moli bicromat care contin 1,2molO
K2Cr2O7 +4H2SO4=> K2SO4+Cr2(SO4)3+4H2O+3O
1mol.............................................................................3mol
x.......................................................................................1,2mol
calculeaza x !!!!
II
O
-CALCULEZ masa de compus pur
p/100= m,pur/m,impur-
80/100= m,pur/26,25----> m,pur= 21g
-calculez numar de moli compus, cu M(miu)=(5x12gC+10gH)/mol=70g/mol
n(niu)= m/M
n= 21g/70g/mol=0,3mol 2metil 1 butena
- calculez moli O, din ecuatie
1mol compus..........4molO
0,3mol..........................x= 1,2molO
-calculez moli bicromat care contin 1,2molO
K2Cr2O7 +4H2SO4=> K2SO4+Cr2(SO4)3+4H2O+3O
1mol.............................................................................3mol
x.......................................................................................1,2mol
calculeaza x !!!!
3·| 2meti1butena +4[O] ⇒ CH3-CO-CH3 + CO2 + H2O 4·| K2Cr2O7 + 4H2SO4 ⇒ K2SO4 + Cr2(SO4)3 + 4H2O + 3[O]
n alchena = 26,25·0,8/ 70 = 0,3 moli
nK2Cr2O7 = 4·0,3/3 = 0,4 moli
n alchena = 26,25·0,8/ 70 = 0,3 moli
nK2Cr2O7 = 4·0,3/3 = 0,4 moli