3x-2y=11 <=>
3x=2y+11
x=(2y+11)/3 (1)
Inlocuind (1) in relatia initiala se obtine:
(2y+11)/3-2y=11<=>
(2y+11)/3-6y/3=11 <=>
(2y+11-6y)/3=11 <=>
(11-4y)/3=11 <=>
11-4y=33 <=>
4y+33=11 <=>
4y=-22 <=>
y=-22/4 <=>
y=-11/2
Dar x=(2y+11)/3 <=>
x=(2(-11/2)+11)/3 <=>
x=(-11+11)/3 <=>
x=0
Asadar x=0 si y=-11/3
