Răspuns :
[tex]a= log_{3}2
[/tex]
[tex]3a=3* log_{3}2=log_{3}2^3= log_{3}8 [/tex]
[tex]1+3a=1+ log_{3}8= log_{3}3+ log_{3}8= log_{3}(8*3)=log _{3}24 [/tex]
[tex]3a=3* log_{3}2=log_{3}2^3= log_{3}8 [/tex]
[tex]1+3a=1+ log_{3}8= log_{3}3+ log_{3}8= log_{3}(8*3)=log _{3}24 [/tex]
Să reformulăm :
[tex]\it a = log_3 2 \Longrightarrow log_324=1+3a.[/tex]
R:
[tex]\it log_3 24 =log_3 3\cdot8= log_3 3 +log_38 =1+log_32^3=1 +3log_32 =[/tex]
[tex]\it= 1+3a.[/tex]
..
[tex]\it a = log_3 2 \Longrightarrow log_324=1+3a.[/tex]
R:
[tex]\it log_3 24 =log_3 3\cdot8= log_3 3 +log_38 =1+log_32^3=1 +3log_32 =[/tex]
[tex]\it= 1+3a.[/tex]
..