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calculati [(2^5)^2+2^5-7^0]÷[(2^2)^5+2^2×2^3-3^8÷3^8]

Răspuns :

Humbert
[(2^5)^2+2^5-7^0]:[(2^2)^5+2^2*2^3-3^8:3^8]=(2^10+2^5-1):(2^10+2^5-1)=1

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