[3^48÷3^18+(2^4)^5+6^23÷6^13]:[(3^5)^2×(2^2)^5+3^17×3^13+(2^5)^4]=


Va rog, ajutati-ma! Dau coronita pentru cine raspunde corect.
PS: Cand am scris ^ , inseamna "la puterea".