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(a+b+c+d+e):21=9,rest 6.a,b,d,e sunt consecutive.Aflati numarul.

Răspuns :

ALIANTA50
a+a+1+a+2+a+3+a+4=21*9+6
5a+10=195
5a=195-10=185
a=185/5
a=37
a+a+1+a+2+a+3+a+4=21*9+6
5a+10=195
5a=195-10=185
a=185:5
a=37
a=37 b=38 c=39 d=40e=41
(37+38+39+40+41):21=9rest 6
195:21=9rest 6

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