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4x²+24x+37=0
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Răspuns :

Anamariaangel
[tex]4x^{2} +24x+37=0[/tex]
Δ=[tex]b^{2} -4ac=(24 )^{2} -4*4*37=576-592=-16[/tex]

[tex] x_{1} = \frac{-b- i\sqrt{-delta} }{2a} = \frac{-24- i\sqrt{-(-16)} }{8}= \frac{-24-4i}{8} = \frac{4(-6-i)}{8}= \frac{-6-i}{2} [/tex]

[tex]x_{1} = \frac{-b+ i\sqrt{-delta} }{2a} = \frac{-24+ i\sqrt{-(-16)} }{8}= \frac{-24+4i}{8} = \frac{4(-6+i)}{8}= \frac{-6-i}{2}[/tex]

S={[tex]\frac{-6-i}{2};\frac{-6+i}{2}[/tex]}