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a fost răspuns

determinati nr naturale n pentru care 2n+6 pe n+1 apartine numereleor naturale

Răspuns :

Sanduurzica
n=0
2*0+6/0+1=6/1=6∈N
n=1
2*1+6/1+1=6/2=3∈N
n=2
2*2+6/2+1=10/3=3,(3)∉N
n=3
2*3+6/3+1=12/4=3∈N
n=4
2*4+6/4+1=14/5=2,8∉N
n=5
2*5+6/5+1=16/6=2,(6)∉N
n=6
2*6+6/6+1=18/7=2,571∉N
n=7
2*7+6/7+1=20/8=2,5∉N
n=8
2*8+6/8+1=22/9=2,(4)∉N
n=9
2*9+6/9+1=24/10=2,4∉N
R: n=0 ; 1 ; 3

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