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efectuati:3x[3+3x(3^3-3^5:3^3)]+2x3^2

Răspuns :

3x[3+3x(3^3-3^5:3^3)]+2x3^2 =

3x[3+3x(3^3-3^2)]+2x3^2 =

3x[3+3x3^2x(3-1)]+2x3^2 =

3x[3+3^3x2]+2x3^2 =

3^2+3^4x2+2x3^2 =

3x3^2+2x3^4=

3^3+2x3^4=

3^3x(1+2x3)=

3^3x7=

27x7=

189

Am atasat poza cu rezolvarea .Bafta !
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