Răspuns :
ti-l explic doar pe primul.
Deci ai 2^17 vs 4^8; 4= 2^2 => 2^17 vs 2^2^8 = 2^17 vs 2^2*8 = 2^17 vs 2^16 => 2^17 > 4^8. (sper ca ai inteles)
Deci ai 2^17 vs 4^8; 4= 2^2 => 2^17 vs 2^2^8 = 2^17 vs 2^2*8 = 2^17 vs 2^16 => 2^17 > 4^8. (sper ca ai inteles)
a) 2 ^17 sau 4 ^ 8
4^8=(2^2)^8=2^16
cum 17>16
2^17>4^8
b)4 ^9 sau 8 ^ 6
4^9=(2^2)^9=2^18
8^6=(2^3)^6=2^18
cum 18=18 => 4^9=8^6
c) 3 ^15 sau 27 ^ 6
27^6=(3^3)^6=3^18
15<18=>3^15<27^6
d ) 8 ^10 < 17 ^7
e)5 ^31 >27^ 7
g ) 5 ^40 sau 125 ^13
5^40 > 5^39
h ) 25 ^13 sau 125 ^9
5^26 <5^27
i) 7^121 sau 49 ^ 60 .
7 ^121<7^120
4^8=(2^2)^8=2^16
cum 17>16
2^17>4^8
b)4 ^9 sau 8 ^ 6
4^9=(2^2)^9=2^18
8^6=(2^3)^6=2^18
cum 18=18 => 4^9=8^6
c) 3 ^15 sau 27 ^ 6
27^6=(3^3)^6=3^18
15<18=>3^15<27^6
d ) 8 ^10 < 17 ^7
e)5 ^31 >27^ 7
g ) 5 ^40 sau 125 ^13
5^40 > 5^39
h ) 25 ^13 sau 125 ^9
5^26 <5^27
i) 7^121 sau 49 ^ 60 .
7 ^121<7^120