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Mariana29032001
a fost răspuns

Sa se descompuna in factori utilizand factoru comun
(x+5)(x-1)+(x-1)(3x-2)
(x+2)(x+5)-(x+3)(x+2)
(3x-2)(x-4)-(-3x-7)(x-4)

Răspuns :

CarMina03
(x+5)(x-1)+(x-1)(3x-2)=(x-1)(x+5+3x-2)=(x-1)(4x+3)

(x+2)(x+5)-(x+3)(x+2)=(x+2)(x+5-x-3)=2(x+2)

(3x-2)(x-4)-(-3x-7)(x-4)=(x-4)(3x-2+3x+7)=(x-4)(6x+5)

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