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a fost răspuns

2^100:[2^50×2^48+(2^10×2^15)^5:2^27+(5^76:5^75-3)^90×2^8+2^98]

Răspuns :

Ancarodica
2¹⁰⁰: [2⁵⁰⁺⁴⁸+(2¹⁰⁺¹⁵)⁵ : 2²⁷+(5-3)⁹⁰x2⁸+2⁹⁸]= 2¹⁰⁰ :(2⁹⁸+2²⁵°⁵ :2²⁷+2⁹⁰x2⁸+2⁹⁸)=
2¹⁰⁰ : (2⁹⁸+2¹²⁵⁻²⁷+2⁹⁸+2⁹⁸)= 2¹⁰⁰ : (2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸)=2¹⁰⁰ :(2⁹⁸x4)=2¹⁰⁰ :(2⁹⁸x2²)=
2¹⁰⁰ :2¹⁰⁰=1

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